Oswego Outbreak Investigation Assignment

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Oswego Outbreak Investigation Assignment

PUB-540-O500: Principles of Epidemiology

Oswego Outbreak Investigation

The average incubation period for gastrointestinal illness is 6 hours 13 minutes. To arrive at this, one subtracts the time when each patient developed signs for the disease from the time of exposure, at 6 p.m. to 11 p.m. on April 18. Thus, subtracting each reported case from the time the patients had their supper helps determine the hours it took them to show signs. The resulting answer for each case is then multiplied by the number of people who developed symptoms at that same time. For example, on the epi curve, case one was reported at 3 p.m., four hours after the child had a vanilla ice cream. Each patient’s time before showing signs of the disease is then summed, which comes to 280.75 hours, divided by the total number of cases, which is 45.¿6.23hours.To convert 0.23 hours into minutes, one multiplies it by 60 minutes which comes to 13.8minutes. Therefore, the average incubation period for the disease is 6h 13 minutes. The epi curve shows the source of the illness was vanilla ice cream considering that patient #52 suffered after having a dish. The transmission mode was a vehicle, which was the vanilla ice cream, as it was contaminated with disease-causing microbes. Potential Infectious Agents. Infectious agents including Staphylococcus aureus and albus were found on the vanilla ice-cream. The two are potential causes of the infection. Staphylococcus aureus and albus cause Staph disease, whose signs and symptoms are nausea, vomiting, diarrhea, dehydration, and low pressure (Mayo Clinic, 2020). Some of these signs were reported through clinical descriptions concerning increased disease cases.

Oswego Outbreak Investigation Assignment